1/3(n-1/3)=1/6n

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Solution for 1/3(n-1/3)=1/6n equation:


n in (-oo:+oo)

(1/3)*(n-(1/3)) = (1/6)*n // - (1/6)*n

(1/3)*(n-(1/3))-((1/6)*n) = 0

(1/3)*(n-1/3)+(-1/6)*n = 0

1/3*(n-1/3)-n/6 = 0

(1/3*6*(n-1/3))/6-n/6 = 0

1/3*6*(n-1/3)-n = 0

n-2/3 = 0

(n-2/3)/6 = 0

(n-2/3)/6 = 0 // * 6

n-2/3 = 0

n-2/3 = 0 // + 2/3

n = 2/3

n = 2/3

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