1/3(n+7)=1/6(3n-5)

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Solution for 1/3(n+7)=1/6(3n-5) equation: 


n in (-oo:+oo)

(1/3)*(n+7) = (1/6)*(3*n-5) // - (1/6)*(3*n-5)

(1/3)*(n+7)-((1/6)*(3*n-5)) = 0

(1/3)*(n+7)+(-1/6)*(3*n-5) = 0

1/3*(n+7)-1/6*(3*n-5) = 0

1/3*(n+7)-1/6*(3*n-5) = 0

19/6-1/6*n = 0

19/6-1/6*n = 0

19/6-1/6*n = 0 // - 19/6

-1/6*n = -19/6 // : -1/6

n = -19/6/(-1/6)

n = 19

n = 19

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