1/3(n+2)-4=-2/3(n-1)

Solution for 1/3(n+2)-4=-2/3(n-1) equation:

1/3(n+2)-4=-2/3(n-1)

We move all terms to the left:

1/3(n+2)-4-(-2/3(n-1))=0


Domain of the equation: 3(n+2)!=0

n∈R



Domain of the equation: 3(n-1))!=0

n∈R


We calculate fractions


(3nn/(3(n+2)*3(n-1)))+(-(-6nn)/(3(n+2)*3(n-1)))-4=0


We calculate terms in parentheses: +(3nn/(3(n+2)*3(n-1))), so:

3nn/(3(n+2)*3(n-1))

We multiply all the terms by the denominator


3nn

Back to the equation:

+(3nn)



We calculate terms in parentheses: +(-(-6nn)/(3(n+2)*3(n-1))), so:

-(-6nn)/(3(n+2)*3(n-1))

We multiply all the terms by the denominator


-(-6nn)

We get rid of parentheses

6nn

Back to the equation:

+(6nn)


We move all terms containing n to the left, all other terms to the right

3nn+6nn=4