1/3(n+1)=2/6(3n-5)

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Solution for 1/3(n+1)=2/6(3n-5) equation: 



1/3(n+1)=2/6(3n-5)

We move all terms to the left:

1/3(n+1)-(2/6(3n-5))=0



Domain of the equation: 3(n+1)!=0

n∈R





Domain of the equation: 6(3n-5))!=0

n∈R



We calculate fractions


(6n3/(3(n+1)*6(3n-5)))+(-6nn/(3(n+1)*6(3n-5)))=0



We calculate terms in parentheses: +(6n3/(3(n+1)*6(3n-5))), so:

6n3/(3(n+1)*6(3n-5))

We multiply all the terms by the denominator


6n3

We add all the numbers together, and all the variables

6n^3

We do not support enpression: n^3

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