1/3(j+2)=3j

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Solution for 1/3(j+2)=3j equation: 



1/3(j+2)=3j

We move all terms to the left:

1/3(j+2)-(3j)=0



Domain of the equation: 3(j+2)!=0

j∈R



We add all the numbers together, and all the variables

-3j+1/3(j+2)=0

We multiply all the terms by the denominator


-3j*3(j+2)+1=0

Wy multiply elements

-9j^2(j+1=0

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