1/3(d-8)-7/2(5d-3)=7/6

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Solution for 1/3(d-8)-7/2(5d-3)=7/6 equation: 


d in (-oo:+oo)

(1/3)*(d-8)-((7/2)*(5*d-3)) = 7/6 // - 7/6

(1/3)*(d-8)-((7/2)*(5*d-3))-(7/6) = 0

(1/3)*(d-8)+(-7/2)*(5*d-3)-7/6 = 0

1/3*(d-8)-7/2*(5*d-3)-7/6 = 0

(1/3*6*(d-8))/6+(-7/2*6*(5*d-3))/6-7/6 = 0

1/3*6*(d-8)-7/2*6*(5*d-3)-7 = 0

47-103*d-7 = 0

40-103*d = 0

(40-103*d)/6 = 0

(40-103*d)/6 = 0 // * 6

40-103*d = 0

40-103*d = 0 // - 40

-103*d = -40 // : -103

d = -40/(-103)

d = 40/103

d = 40/103

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