1/3(c-6)=1/9c

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Solution for 1/3(c-6)=1/9c equation: 


c in (-oo:+oo)

(1/3)*(c-6) = (1/9)*c // - (1/9)*c

(1/3)*(c-6)-((1/9)*c) = 0

(1/3)*(c-6)+(-1/9)*c = 0

1/3*(c-6)-c/9 = 0

(1/3*9*(c-6))/9-c/9 = 0

1/3*9*(c-6)-c = 0

2*c-18 = 0

(2*c-18)/9 = 0

(2*c-18)/9 = 0 // * 9

2*c-18 = 0

2*c-18 = 0 // + 18

2*c = 18 // : 2

c = 18/2

c = 9

c = 9

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