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1/3(c-1)=1/6(3c-5)
We move all terms to the left:
1/3(c-1)-(1/6(3c-5))=0
Domain of the equation: 3(c-1)!=0
c∈R
Domain of the equation: 6(3c-5))!=0We calculate fractions
c∈R
(6c3/(3(c-1)*6(3c-5)))+(-3cc/(3(c-1)*6(3c-5)))=0
We calculate terms in parentheses: +(6c3/(3(c-1)*6(3c-5))), so:
6c3/(3(c-1)*6(3c-5))
We multiply all the terms by the denominator
6c3
We add all the numbers together, and all the variables
6c^3
We do not support ecpression: c^3
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