1/3(c+1)=1/6(3c-6)

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Solution for 1/3(c+1)=1/6(3c-6) equation: 



1/3(c+1)=1/6(3c-6)

We move all terms to the left:

1/3(c+1)-(1/6(3c-6))=0



Domain of the equation: 3(c+1)!=0

c∈R





Domain of the equation: 6(3c-6))!=0

c∈R



We calculate fractions


(6c3/(3(c+1)*6(3c-6)))+(-3cc/(3(c+1)*6(3c-6)))=0



We calculate terms in parentheses: +(6c3/(3(c+1)*6(3c-6))), so:

6c3/(3(c+1)*6(3c-6))

We multiply all the terms by the denominator


6c3

We add all the numbers together, and all the variables

6c^3

We do not support ecpression: c^3

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