1/3(a-2)=1/2(a+6)

Solution for 1/3(a-2)=1/2(a+6) equation:

1/3(a-2)=1/2(a+6)

We move all terms to the left:

1/3(a-2)-(1/2(a+6))=0


Domain of the equation: 3(a-2)!=0

a∈R



Domain of the equation: 2(a+6))!=0

a∈R


We calculate fractions


(2aa/(3(a-2)*2(a+6)))+(-3aa/(3(a-2)*2(a+6)))=0


We calculate terms in parentheses: +(2aa/(3(a-2)*2(a+6))), so:

2aa/(3(a-2)*2(a+6))

We multiply all the terms by the denominator


2aa

Back to the equation:

+(2aa)



We calculate terms in parentheses: +(-3aa/(3(a-2)*2(a+6))), so:

-3aa/(3(a-2)*2(a+6))

We multiply all the terms by the denominator


-3aa

Back to the equation:

+(-3aa)


We get rid of parentheses

2aa-3aa=0