1/3(9z-6)

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Solution for 1/3(9z-6) equation: 


z in (-oo:+oo)

(1/3)*(9*z-6) = 0

1/3*(9*z-6) = 0

( 1/3 )

1/3 = 0

z belongs to the empty set

( 9*z-6 )

9*z-6 = 0 // + 6

9*z = 6 // : 9

z = 6/9

z = 2/3

z = 2/3

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