1/3(9x-6)=8x+38

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Solution for 1/3(9x-6)=8x+38 equation: 



1/3(9x-6)=8x+38

We move all terms to the left:

1/3(9x-6)-(8x+38)=0



Domain of the equation: 3(9x-6)!=0

x∈R



We get rid of parentheses

1/3(9x-6)-8x-38=0

We multiply all the terms by the denominator


-8x*3(9x-6)-38*3(9x-6)+1=0

Wy multiply elements

-24x^2(9-114x(9+1=0

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