1/3(9x-6)=3(x+2)-8

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Solution for 1/3(9x-6)=3(x+2)-8 equation: 


x in (-oo:+oo)

(1/3)*(9*x-6) = 3*(x+2)-8 // - 3*(x+2)-8

(1/3)*(9*x-6)-(3*(x+2))+8 = 0

(1/3)*(9*x-6)-3*(x+2)+8 = 0

1/3*(9*x-6)-3*(x+2)+8 = 0

1/3*(9*x-6)-3*(x+2)+8 = 0

8-8 = 0

0 = 0

0 = 0

x belongs to the empty set

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