1/3(9x+9)=1/6(24x+42)

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Solution for 1/3(9x+9)=1/6(24x+42) equation: 



1/3(9x+9)=1/6(24x+42)

We move all terms to the left:

1/3(9x+9)-(1/6(24x+42))=0



Domain of the equation: 3(9x+9)!=0

x∈R





Domain of the equation: 6(24x+42))!=0

x∈R



We calculate fractions


(6x2/(3(9x+9)*6(24x+42)))+(-3x9/(3(9x+9)*6(24x+42)))=0



We calculate terms in parentheses: +(6x2/(3(9x+9)*6(24x+42))), so:

6x2/(3(9x+9)*6(24x+42))

We multiply all the terms by the denominator


6x2

We add all the numbers together, and all the variables

6x^2

Back to the equation:

+(6x^2)





We calculate terms in parentheses: +(-3x9/(3(9x+9)*6(24x+42))), so:

-3x9/(3(9x+9)*6(24x+42))

We multiply all the terms by the denominator


-3x9

We add all the numbers together, and all the variables

-3x^9

We do not support expression: x^9

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