1/3(9x+33)=41

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Solution for 1/3(9x+33)=41 equation: 



1/3(9x+33)=41

We move all terms to the left:

1/3(9x+33)-(41)=0



Domain of the equation: 3(9x+33)!=0

x∈R



We multiply all the terms by the denominator


-41*3(9x+33)+1=0

Wy multiply elements

-123x(9+1=0

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