1/3(9x+12)+x=36

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Solution for 1/3(9x+12)+x=36 equation: 



1/3(9x+12)+x=36

We move all terms to the left:

1/3(9x+12)+x-(36)=0



Domain of the equation: 3(9x+12)!=0

x∈R



We add all the numbers together, and all the variables

x+1/3(9x+12)-36=0

We multiply all the terms by the denominator


x*3(9x+12)-36*3(9x+12)+1=0

Wy multiply elements

3x^2(9-108x(9+1=0

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