1/3(9n-33)=-6n-11+9n

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Solution for 1/3(9n-33)=-6n-11+9n equation: 



1/3(9n-33)=-6n-11+9n

We move all terms to the left:

1/3(9n-33)-(-6n-11+9n)=0



Domain of the equation: 3(9n-33)!=0

n∈R



We add all the numbers together, and all the variables

1/3(9n-33)-(3n-11)=0

We get rid of parentheses

1/3(9n-33)-3n+11=0

We multiply all the terms by the denominator


-3n*3(9n-33)+11*3(9n-33)+1=0

Wy multiply elements

-9n^2(9+33n(9+1=0

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