1/3(9m+12)=m-12

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Solution for 1/3(9m+12)=m-12 equation: 



1/3(9m+12)=m-12

We move all terms to the left:

1/3(9m+12)-(m-12)=0



Domain of the equation: 3(9m+12)!=0

m∈R



We get rid of parentheses

1/3(9m+12)-m+12=0

We multiply all the terms by the denominator


-m*3(9m+12)+12*3(9m+12)+1=0

Wy multiply elements

-3m^2(9+36m(9+1=0

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