1/3(9b+1)=1b-1

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Solution for 1/3(9b+1)=1b-1 equation: 



1/3(9b+1)=1b-1

We move all terms to the left:

1/3(9b+1)-(1b-1)=0



Domain of the equation: 3(9b+1)!=0

b∈R



We add all the numbers together, and all the variables

1/3(9b+1)-(b-1)=0

We get rid of parentheses

1/3(9b+1)-b+1=0

We multiply all the terms by the denominator


-b*3(9b+1)+1*3(9b+1)+1=0

Wy multiply elements

-3b^2(9+3b(9+1=0

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