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1/3(9+9x)=12+2x
We move all terms to the left:
1/3(9+9x)-(12+2x)=0
Domain of the equation: 3(9+9x)!=0We add all the numbers together, and all the variables
x∈R
1/3(9x+9)-(2x+12)=0
We get rid of parentheses
1/3(9x+9)-2x-12=0
We multiply all the terms by the denominator
-2x*3(9x+9)-12*3(9x+9)+1=0
Wy multiply elements
-6x^2(9-36x(9+1=0
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