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1/3(8r+12)=3+2r
We move all terms to the left:
1/3(8r+12)-(3+2r)=0
Domain of the equation: 3(8r+12)!=0We add all the numbers together, and all the variables
r∈R
1/3(8r+12)-(2r+3)=0
We get rid of parentheses
1/3(8r+12)-2r-3=0
We multiply all the terms by the denominator
-2r*3(8r+12)-3*3(8r+12)+1=0
Wy multiply elements
-6r^2(8-9r(8+1=0
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