1/3(7y-1)+1/6(4y+7)=3y+5/6

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Solution for 1/3(7y-1)+1/6(4y+7)=3y+5/6 equation: 



1/3(7y-1)+1/6(4y+7)=3y+5/6

We move all terms to the left:

1/3(7y-1)+1/6(4y+7)-(3y+5/6)=0



Domain of the equation: 3(7y-1)!=0

y∈R





Domain of the equation: 6(4y+7)!=0

y∈R



We add all the numbers together, and all the variables

1/3(7y-1)+1/6(4y+7)-(+3y+5/6)=0

We get rid of parentheses

1/3(7y-1)+1/6(4y+7)-3y-5/6=0

We calculate fractions


-3y+(36y4/(3(7y-1)*6(4y+7)*6)+(3y7/(3(7y-1)*6(4y+7)*6)+(-15y7/(3(7y-1)*6(4y+7)*6)=0



We calculate terms in parentheses: +(36y4/(3(7y-1)*6(4y+7)*6)+(3y7/(3(7y-1)*6(4y+7)*6)+(-15y7/(3(7y-1)*6(4y+7)*6), so:

36y4/(3(7y-1)*6(4y+7)*6)+(3y7/(3(7y-1)*6(4y+7)*6)+(-15y7/(3(7y-1)*6(4y+7)*6

We can not solve this equation

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