1/3(6z+18)=3z-9

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Solution for 1/3(6z+18)=3z-9 equation: 



1/3(6z+18)=3z-9

We move all terms to the left:

1/3(6z+18)-(3z-9)=0



Domain of the equation: 3(6z+18)!=0

z∈R



We get rid of parentheses

1/3(6z+18)-3z+9=0

We multiply all the terms by the denominator


-3z*3(6z+18)+9*3(6z+18)+1=0

Wy multiply elements

-9z^2(6+27z(6+1=0

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