1/3(6y-12)=8-4y

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Solution for 1/3(6y-12)=8-4y equation: 


y in (-oo:+oo)

(1/3)*(6*y-12) = 8-(4*y) // - 8-(4*y)

(1/3)*(6*y-12)+4*y-8 = 0

1/3*(6*y-12)+4*y-8 = 0

1/3*(6*y-12)+4*y-8 = 0

6*y-8-4 = 0

6*y-12 = 0

6*y-12 = 0

6*y-12 = 0 // + 12

6*y = 12 // : 6

y = 12/6

y = 2

y = 2

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