1/3(6y+9)=1/2(8y-2)

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Solution for 1/3(6y+9)=1/2(8y-2) equation: 



1/3(6y+9)=1/2(8y-2)

We move all terms to the left:

1/3(6y+9)-(1/2(8y-2))=0



Domain of the equation: 3(6y+9)!=0

y∈R





Domain of the equation: 2(8y-2))!=0

y∈R



We calculate fractions


(2y8/(3(6y+9)*2(8y-2)))+(-3y6/(3(6y+9)*2(8y-2)))=0



We calculate terms in parentheses: +(2y8/(3(6y+9)*2(8y-2))), so:

2y8/(3(6y+9)*2(8y-2))

We multiply all the terms by the denominator


2y8

We add all the numbers together, and all the variables

2y^8

We do not support eypression: y^8

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