1/3(6x-9)+1=15-1/2(20-10x)

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Solution for 1/3(6x-9)+1=15-1/2(20-10x) equation: 



1/3(6x-9)+1=15-1/2(20-10x)

We move all terms to the left:

1/3(6x-9)+1-(15-1/2(20-10x))=0



Domain of the equation: 3(6x-9)!=0

x∈R





Domain of the equation: 2(20-10x))!=0

x∈R



We add all the numbers together, and all the variables

1/3(6x-9)-(15-1/2(-10x+20))+1=0

We calculate fractions


(2x(-)/(3(6x-9)*2(-10x+20)))+(-(-3x6)/(3(6x-9)*2(-10x+20)))+1=0



We calculate terms in parentheses: +(2x(-)/(3(6x-9)*2(-10x+20))), so:

2x(-)/(3(6x-9)*2(-10x+20))

We add all the numbers together, and all the variables

2x0/(3(6x-9)*2(-10x+20))

We multiply all the terms by the denominator


2x0

We add all the numbers together, and all the variables

2x

Back to the equation:

+(2x)





We calculate terms in parentheses: +(-(-3x6)/(3(6x-9)*2(-10x+20))), so:

-(-3x6)/(3(6x-9)*2(-10x+20))

We add all the numbers together, and all the variables

-(-3x^6)/(3(6x-9)*2(-10x+20))

We multiply all the terms by the denominator


-(-3x^6)

We do not support expression: x^6

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