1/3(6x-5)=1/3(x+10)

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Solution for 1/3(6x-5)=1/3(x+10) equation: 



1/3(6x-5)=1/3(x+10)

We move all terms to the left:

1/3(6x-5)-(1/3(x+10))=0



Domain of the equation: 3(6x-5)!=0

x∈R





Domain of the equation: 3(x+10))!=0

x∈R



We calculate fractions


(3xx/(3(6x-5)*3(x+10)))+(-3x6/(3(6x-5)*3(x+10)))=0



We calculate terms in parentheses: +(3xx/(3(6x-5)*3(x+10))), so:

3xx/(3(6x-5)*3(x+10))

We multiply all the terms by the denominator


3xx

Back to the equation:

+(3xx)





We calculate terms in parentheses: +(-3x6/(3(6x-5)*3(x+10))), so:

-3x6/(3(6x-5)*3(x+10))

We multiply all the terms by the denominator


-3x6

We add all the numbers together, and all the variables

-3x^6

We do not support expression: x^6

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