1/3(6x-12)+27=57x+1

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Solution for 1/3(6x-12)+27=57x+1 equation: 



1/3(6x-12)+27=57x+1

We move all terms to the left:

1/3(6x-12)+27-(57x+1)=0



Domain of the equation: 3(6x-12)!=0

x∈R



We get rid of parentheses

1/3(6x-12)-57x-1+27=0

We multiply all the terms by the denominator


-57x*3(6x-12)-1*3(6x-12)+27*3(6x-12)+1=0

Wy multiply elements

-171x^2(6-3x(6+81x(6+1=0

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