1/3(6x+24)-20=-1/412x-72

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Solution for 1/3(6x+24)-20=-1/412x-72 equation: 



1/3(6x+24)-20=-1/412x-72

We move all terms to the left:

1/3(6x+24)-20-(-1/412x-72)=0



Domain of the equation: 3(6x+24)!=0

x∈R





Domain of the equation: 412x-72)!=0

x∈R



We get rid of parentheses

1/3(6x+24)+1/412x+72-20=0

We calculate fractions


412x/(7416x^2+29664x)+(3x6/(7416x^2+29664x)+72-20=0

We calculate fractions

We do not support expression: x^3

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