1/3(6x+12)-2(x-7)=19

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Solution for 1/3(6x+12)-2(x-7)=19 equation: 


x in (-oo:+oo)

(1/3)*(6*x+12)-(2*(x-7)) = 19 // - 19

(1/3)*(6*x+12)-(2*(x-7))-19 = 0

(1/3)*(6*x+12)-2*(x-7)-19 = 0

1/3*(6*x+12)-2*(x-7)-19 = 0

1/3*(6*x+12)-2*(x-7)-19 = 0

18-19 = 0

-1 = 0

-1 = 0

x belongs to the empty set

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