1/3(6m-12)=m+7

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Solution for 1/3(6m-12)=m+7 equation: 



1/3(6m-12)=m+7

We move all terms to the left:

1/3(6m-12)-(m+7)=0



Domain of the equation: 3(6m-12)!=0

m∈R



We get rid of parentheses

1/3(6m-12)-m-7=0

We multiply all the terms by the denominator


-m*3(6m-12)-7*3(6m-12)+1=0

Wy multiply elements

-3m^2(6-21m(6+1=0

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