1/3(6h+3)-4h+2=-2(h-3)+3h

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Solution for 1/3(6h+3)-4h+2=-2(h-3)+3h equation: 



1/3(6h+3)-4h+2=-2(h-3)+3h

We move all terms to the left:

1/3(6h+3)-4h+2-(-2(h-3)+3h)=0



Domain of the equation: 3(6h+3)!=0

h∈R



We add all the numbers together, and all the variables

-4h+1/3(6h+3)-(-2(h-3)+3h)+2=0

We multiply all the terms by the denominator


-4h*3(6h+3)-((-2(h-3)+3h))*3(6h+3)+2*3(6h+3)+1=0



We calculate terms in parentheses: -((-2(h-3)+3h))*3(6h+3), so:

(-2(h-3)+3h))*3(6h+3



Wy multiply elements

-12h^2(6-((-2(h-3)+3h))*3(6h+3)+6h(6+1=0

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