1/3(6f+3)=7-f

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Solution for 1/3(6f+3)=7-f equation: 



1/3(6f+3)=7-f

We move all terms to the left:

1/3(6f+3)-(7-f)=0



Domain of the equation: 3(6f+3)!=0

f∈R



We add all the numbers together, and all the variables

1/3(6f+3)-(-1f+7)=0

We get rid of parentheses

1/3(6f+3)+1f-7=0

We multiply all the terms by the denominator


1f*3(6f+3)-7*3(6f+3)+1=0

Wy multiply elements

3f^2(6-21f(6+1=0

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