1/3(6a+48)-20=1/4(12a-72)

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Solution for 1/3(6a+48)-20=1/4(12a-72) equation: 



1/3(6a+48)-20=1/4(12a-72)

We move all terms to the left:

1/3(6a+48)-20-(1/4(12a-72))=0



Domain of the equation: 3(6a+48)!=0

a∈R





Domain of the equation: 4(12a-72))!=0

a∈R



We calculate fractions


(4a1/(3(6a+48)*4(12a-72)))+(-3a6/(3(6a+48)*4(12a-72)))-20=0



We calculate terms in parentheses: +(4a1/(3(6a+48)*4(12a-72))), so:

4a1/(3(6a+48)*4(12a-72))

We multiply all the terms by the denominator


4a1

We add all the numbers together, and all the variables

4a

Back to the equation:

+(4a)





We calculate terms in parentheses: +(-3a6/(3(6a+48)*4(12a-72))), so:

-3a6/(3(6a+48)*4(12a-72))

We multiply all the terms by the denominator


-3a6

We add all the numbers together, and all the variables

-3a^6

We do not support eapression: a^6

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