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1/3(6-9x)=3x-2
We move all terms to the left:
1/3(6-9x)-(3x-2)=0
Domain of the equation: 3(6-9x)!=0We add all the numbers together, and all the variables
x∈R
1/3(-9x+6)-(3x-2)=0
We get rid of parentheses
1/3(-9x+6)-3x+2=0
We multiply all the terms by the denominator
-3x*3(-9x+6)+2*3(-9x+6)+1=0
Wy multiply elements
-9x^2(-+6x(-+1=0
We use the square of the difference formula
-9x^2(-6x(-1=0
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