1/3(6-9)+2=1/2(2x-16)

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Solution for 1/3(6-9)+2=1/2(2x-16) equation: 



1/3(6-9)+2=1/2(2x-16)

We move all terms to the left:

1/3(6-9)+2-(1/2(2x-16))=0



Domain of the equation: 2(2x-16))!=0

x∈R



We add all the numbers together, and all the variables

-(1/2(2x-16))+2+1/3(-3)=0

We calculate fractions


()/(2(2x-16))*3()+(2x2/(2(2x-16))*3()+2=0



We calculate terms in parentheses: +()/(2(2x-16))*3(), so:

)/(2(2x-16))*3(

We multiply all the terms by the denominator


)

We add all the numbers together, and all the variables



Back to the equation:

+()



We multiply all the terms by the denominator


(2x2=0

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