1/3(5-3(x-2))=1/6(x+1)

Solution for 1/3(5-3(x-2))=1/6(x+1) equation:

1/3(5-3(x-2))=1/6(x+1)

We move all terms to the left:

1/3(5-3(x-2))-(1/6(x+1))=0


Domain of the equation: 3(5-3(x-2))!=0

x∈R



Domain of the equation: 6(x+1))!=0

x∈R


We calculate fractions


(6xx/(3(5-3(x-2))*6(x+1)))+(-3x5/(3(5-3(x-2))*6(x+1)))=0


We calculate terms in parentheses: +(6xx/(3(5-3(x-2))*6(x+1))), so:

6xx/(3(5-3(x-2))*6(x+1))

We multiply all the terms by the denominator


6xx

Back to the equation:

+(6xx)



We calculate terms in parentheses: +(-3x5/(3(5-3(x-2))*6(x+1))), so:

-3x5/(3(5-3(x-2))*6(x+1))

We multiply all the terms by the denominator


-3x5

We add all the numbers together, and all the variables

-3x^5

We do not support expression: x^5