1/3(4a-2)=2/5(2a+5)

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Solution for 1/3(4a-2)=2/5(2a+5) equation: 



1/3(4a-2)=2/5(2a+5)

We move all terms to the left:

1/3(4a-2)-(2/5(2a+5))=0



Domain of the equation: 3(4a-2)!=0

a∈R





Domain of the equation: 5(2a+5))!=0

a∈R



We calculate fractions


(5a2/(3(4a-2)*5(2a+5)))+(-6a4/(3(4a-2)*5(2a+5)))=0



We calculate terms in parentheses: +(5a2/(3(4a-2)*5(2a+5))), so:

5a2/(3(4a-2)*5(2a+5))

We multiply all the terms by the denominator


5a2

We add all the numbers together, and all the variables

5a^2

Back to the equation:

+(5a^2)





We calculate terms in parentheses: +(-6a4/(3(4a-2)*5(2a+5))), so:

-6a4/(3(4a-2)*5(2a+5))

We multiply all the terms by the denominator


-6a4

We add all the numbers together, and all the variables

-6a^4

We do not support eapression: a^4

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