1/3(42-18z)=2(8-4z)

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Solution for 1/3(42-18z)=2(8-4z) equation: 


z in (-oo:+oo)

(1/3)*(42-(18*z)) = 2*(8-(4*z)) // - 2*(8-(4*z))

(1/3)*(42-(18*z))-(2*(8-(4*z))) = 0

(1/3)*(42-18*z)-2*(8-4*z) = 0

1/3*(42-18*z)-2*(8-4*z) = 0

1/3*(42-18*z)-2*(8-4*z) = 0

2*z-2 = 0

2*z-2 = 0

2*z-2 = 0 // + 2

2*z = 2 // : 2

z = 2/2

z = 1

z = 1

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