1/3(3y+12)-6=-1/5(10y-35)

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Solution for 1/3(3y+12)-6=-1/5(10y-35) equation: 


y in (-oo:+oo)

(1/3)*(3*y+12)-6 = (-1/5)*(10*y-35) // - (-1/5)*(10*y-35)

(1/3)*(3*y+12)-((-1/5)*(10*y-35))-6 = 0

(1/3)*(3*y+12)+(1/5)*(10*y-35)-6 = 0

1/3*(3*y+12)+1/5*(10*y-35)-6 = 0

1/3*(3*y+12)+1/5*(10*y-35)-6 = 0

3*y-6-3 = 0

3*y-9 = 0

3*y-9 = 0

3*y-9 = 0 // + 9

3*y = 9 // : 3

y = 9/3

y = 3

y = 3

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