1/3(3x-6)=1/2(4x-2)

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Solution for 1/3(3x-6)=1/2(4x-2) equation: 



1/3(3x-6)=1/2(4x-2)

We move all terms to the left:

1/3(3x-6)-(1/2(4x-2))=0



Domain of the equation: 3(3x-6)!=0

x∈R





Domain of the equation: 2(4x-2))!=0

x∈R



We calculate fractions


(2x4/(3(3x-6)*2(4x-2)))+(-3x3/(3(3x-6)*2(4x-2)))=0



We calculate terms in parentheses: +(2x4/(3(3x-6)*2(4x-2))), so:

2x4/(3(3x-6)*2(4x-2))

We multiply all the terms by the denominator


2x4

We add all the numbers together, and all the variables

2x^4

We do not support expression: x^4

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