1/3(3t-7)=t+7/6

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Solution for 1/3(3t-7)=t+7/6 equation: 


t in (-oo:+oo)

(1/3)*(3*t-7) = t+7/6 // - t+7/6

(1/3)*(3*t-7)-t-(7/6) = 0

(1/3)*(3*t-7)-t-7/6 = 0

1/3*(3*t-7)-t-7/6 = 0

(1/3*6*(3*t-7))/6+(6*(-t))/6-7/6 = 0

1/3*6*(3*t-7)+6*(-t)-7 = 0

-14-7 = 0

-21 = 0

-21/6 = 0

-21/6 = 0 // * 6

-21 = 0

t belongs to the empty set

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