1/3(3m-6)1/4(5m+4)+1/5(2m-9)=-3

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Solution for 1/3(3m-6)1/4(5m+4)+1/5(2m-9)=-3 equation: 


m in (-oo:+oo)

(((1/3)*(3*m-6)^1)/4)*(5*m+4)+(1/5)*(2*m-9) = -3 // + 3

(((1/3)*(3*m-6)^1)/4)*(5*m+4)+(1/5)*(2*m-9)+3 = 0

(((1/3)*(3*m-6))/4)*(5*m+4)+(1/5)*(2*m-9)+3 = 0

(1/3*(3*m-6)*(5*m+4))/4+1/5*(2*m-9)+3 = 0

(1/3*(3*m-6)*(5*m+4))/4+(1/5*4*(2*m-9))/4+(3*4)/4 = 0

1/3*(3*m-6)*(5*m+4)+1/5*4*(2*m-9)+3*4 = 0

5*m^2-22/5*m-76/5+12 = 0

5*m^2-22/5*m-16/5 = 0

5*m^2-22/5*m-16/5 = 0

5*m^2-22/5*m-16/5 = 0

DELTA = (-22/5)^2-(-16/5*4*5)

DELTA = 2084/25

DELTA > 0

m = ((2084/25)^(1/2)+22/5)/(2*5) or m = (22/5-(2084/25)^(1/2))/(2*5)

m = ((2084/25)^(1/2)+22/5)/10 or m = (22/5-(2084/25)^(1/2))/10

(m-((22/5-(2084/25)^(1/2))/10))*(m-(((2084/25)^(1/2)+22/5)/10)) = 0

((m-((22/5-(2084/25)^(1/2))/10))*(m-(((2084/25)^(1/2)+22/5)/10)))/4 = 0

((m-((22/5-(2084/25)^(1/2))/10))*(m-(((2084/25)^(1/2)+22/5)/10)))/4 = 0 // * 4

(m-((22/5-(2084/25)^(1/2))/10))*(m-(((2084/25)^(1/2)+22/5)/10)) = 0

( m-(((2084/25)^(1/2)+22/5)/10) )

m-(((2084/25)^(1/2)+22/5)/10) = 0 // + ((2084/25)^(1/2)+22/5)/10

m = ((2084/25)^(1/2)+22/5)/10

( m-((22/5-(2084/25)^(1/2))/10) )

m-((22/5-(2084/25)^(1/2))/10) = 0 // + (22/5-(2084/25)^(1/2))/10

m = (22/5-(2084/25)^(1/2))/10

m in { ((2084/25)^(1/2)+22/5)/10, (22/5-(2084/25)^(1/2))/10 }

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