1/3(3k-1)+2/5(4k+3)=3/5(k-7)+1

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Solution for 1/3(3k-1)+2/5(4k+3)=3/5(k-7)+1 equation: 



1/3(3k-1)+2/5(4k+3)=3/5(k-7)+1

We move all terms to the left:

1/3(3k-1)+2/5(4k+3)-(3/5(k-7)+1)=0



Domain of the equation: 3(3k-1)!=0

k∈R





Domain of the equation: 5(4k+3)!=0

k∈R





Domain of the equation: 5(k-7)+1)!=0

k∈R



We calculate fractions

We do not support ekpression: k^23

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