1/3(3-z)=z

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Solution for 1/3(3-z)=z equation: 



1/3(3-z)=z

We move all terms to the left:

1/3(3-z)-(z)=0



Domain of the equation: 3(3-z)!=0

z∈R



We add all the numbers together, and all the variables

1/3(-1z+3)-z=0

We add all the numbers together, and all the variables

-1z+1/3(-1z+3)=0

We multiply all the terms by the denominator


-1z*3(-1z+3)+1=0

Wy multiply elements

-3z^2(-+1=0

We use the square of the difference formula

-3z^2(-1=0

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