1/3(3-x)=4(2+x)

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Solution for 1/3(3-x)=4(2+x) equation: 



1/3(3-x)=4(2+x)

We move all terms to the left:

1/3(3-x)-(4(2+x))=0



Domain of the equation: 3(3-x)!=0

x∈R



We add all the numbers together, and all the variables

1/3(-1x+3)-(4(x+2))=0

We multiply all the terms by the denominator


-((4(x+2)))*3(-1x+3)+1=0



We calculate terms in parentheses: -((4(x+2)))*3(-1x+3), so:

(4(x+2)))*3(-1x+3

We add all the numbers together, and all the variables

-1x+(4(x+2)))*3(+3

Back to the equation:

-(-1x+(4(x+2)))*3(+3)



We add all the numbers together, and all the variables

-(-1x+(4(x+2)))*33+1=0

We move all terms containing x to the left, all other terms to the right

-(-1x+(4(x+2)))*33=-1

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