1/3(3-x)=1/3(3+x)

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Solution for 1/3(3-x)=1/3(3+x) equation: 



1/3(3-x)=1/3(3+x)

We move all terms to the left:

1/3(3-x)-(1/3(3+x))=0



Domain of the equation: 3(3-x)!=0

x∈R





Domain of the equation: 3(3+x))!=0

x∈R



We add all the numbers together, and all the variables

1/3(-1x+3)-(1/3(x+3))=0

We calculate fractions


(3xx/(3(-1x+3)*3(x+3)))+(-3x0/(3(-1x+3)*3(x+3)))=0



We calculate terms in parentheses: +(3xx/(3(-1x+3)*3(x+3))), so:

3xx/(3(-1x+3)*3(x+3))

We multiply all the terms by the denominator


3xx

Back to the equation:

+(3xx)





We calculate terms in parentheses: +(-3x0/(3(-1x+3)*3(x+3))), so:

-3x0/(3(-1x+3)*3(x+3))

We multiply all the terms by the denominator


-3x0

We add all the numbers together, and all the variables

-3x

Back to the equation:

+(-3x)



We get rid of parentheses

3xx-3x=0

We add all the numbers together, and all the variables

-3x+3xx=0

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