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1/3(3+12y)=6
We move all terms to the left:
1/3(3+12y)-(6)=0
Domain of the equation: 3(3+12y)!=0We add all the numbers together, and all the variables
y∈R
1/3(12y+3)-6=0
We multiply all the terms by the denominator
-6*3(12y+3)+1=0
Wy multiply elements
-18y(1+1=0
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