1/3(2x-7)=1/2(x+3)

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Solution for 1/3(2x-7)=1/2(x+3) equation: 



1/3(2x-7)=1/2(x+3)

We move all terms to the left:

1/3(2x-7)-(1/2(x+3))=0



Domain of the equation: 3(2x-7)!=0

x∈R





Domain of the equation: 2(x+3))!=0

x∈R



We calculate fractions


(2xx/(3(2x-7)*2(x+3)))+(-3x2/(3(2x-7)*2(x+3)))=0



We calculate terms in parentheses: +(2xx/(3(2x-7)*2(x+3))), so:

2xx/(3(2x-7)*2(x+3))

We multiply all the terms by the denominator


2xx

Back to the equation:

+(2xx)





We calculate terms in parentheses: +(-3x2/(3(2x-7)*2(x+3))), so:

-3x2/(3(2x-7)*2(x+3))

We multiply all the terms by the denominator


-3x2

We add all the numbers together, and all the variables

-3x^2

Back to the equation:

+(-3x^2)



We get rid of parentheses

-3x^2+2xx=0

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