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1/3(2x+12)=8+2x
We move all terms to the left:
1/3(2x+12)-(8+2x)=0
Domain of the equation: 3(2x+12)!=0We add all the numbers together, and all the variables
x∈R
1/3(2x+12)-(2x+8)=0
We get rid of parentheses
1/3(2x+12)-2x-8=0
We multiply all the terms by the denominator
-2x*3(2x+12)-8*3(2x+12)+1=0
Wy multiply elements
-6x^2(2-24x(2+1=0
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